A hole in a graph

Plugging in gives $\frac{0}{0}$; look for a common factor.

1. At $x=3$ the numerator and the denominator are both $0$.
2. The numerator factors as $(x-3)(x+2)$.
3. For $x\ne 3$ the ratio equals $x+2$.
4. So the limit is $3+2=5$.

Answer: $5$