Tail of coin flips

Count the outcomes with exactly $4$ heads and exactly $5$ heads, then divide by the total.

1. The total number of equally likely outcomes is $2^5=32$.
2. Exactly $4$ heads can occur in $5$ ways, and exactly $5$ heads in $1$ way.
3. The favorable count is $5+1=6$, so the probability is $\frac{6}{32}$.
4. In lowest terms the probability is $\frac{3}{16}$.

Answer: $\frac{3}{16}$