Learn / Library / Brainteasers

Shared terminal schedule

BrainteasersEasy

$7$ traders use one terminal one after another. Each session lasts $15$ minutes, and there is a break of $5$ minutes between each pair of consecutive sessions, with no break before the first or after the last. How many minutes pass from the start of the first session to the end of the last?

Checking an answer needs JavaScript. The hint and the solution open without it.

Hint

Count the sessions and the gaps separately.

Solution

The sessions take $7 \times 15 = 105$ minutes in total.
$7$ sessions have $6$ gaps between them.
The gaps take $6 \times 5 = 30$ minutes.
The total is $105 + 30 = 135$ minutes, so the answer is $135$ .

Answer: $135$

Next question Back to the library